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x^2+200x=6900
We move all terms to the left:
x^2+200x-(6900)=0
a = 1; b = 200; c = -6900;
Δ = b2-4ac
Δ = 2002-4·1·(-6900)
Δ = 67600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{67600}=260$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(200)-260}{2*1}=\frac{-460}{2} =-230 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(200)+260}{2*1}=\frac{60}{2} =30 $
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